■初等関数研究室■

[0049 名無し生涯学習 2019/06/19(水) 16:40:31.79 ID:529bsc0O0]

(n(n+1)/2-1)^2+(4n^3-6n^2-4n-3(-1)^n+3)/48
(n(n+1)/2-1)^2+(-4n^3+18n^2+28n-3(-1)^n-45)/48