■初等関数研究室■

[188 名無し生涯学習 2019/07/10(水) 20:09:31.33 ID:aK9l5zBu0]

Table[sum[C(2n-1+C(0,n-1)+C(0,n-3)-C(0,n-5)+C(0,n-6),k-1),{n,1,9}],{k,1,20}]
Table[sum[C(2n-1+C(0,6mod n)-C(0,C(3,n-2)-1),k-1),{n,1,9}],{k,1,20}]